Base | Representation |
---|---|
bin | 111111010101001111… |
… | …0100011101000000100 |
3 | 111000001100202022011221 |
4 | 1332222132203220010 |
5 | 4212014023420030 |
6 | 142251320210124 |
7 | 12553210654354 |
oct | 1765236435004 |
9 | 430040668157 |
10 | 136004123140 |
11 | 52751866776 |
12 | 22437609944 |
13 | ca95a85212 |
14 | 6822a6cb64 |
15 | 3810012e7a |
hex | 1faa7a3a04 |
136004123140 has 96 divisors (see below), whose sum is σ = 293119706880. Its totient is φ = 52992423936.
The previous prime is 136004123113. The next prime is 136004123153. The reversal of 136004123140 is 41321400631.
It is a super-2 number, since 2×1360041231402 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 68722671 + ... + 68724649.
It is an arithmetic number, because the mean of its divisors is an integer number (3053330280).
Almost surely, 2136004123140 is an apocalyptic number.
136004123140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
136004123140 is an abundant number, since it is smaller than the sum of its proper divisors (157115583740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136004123140 is a wasteful number, since it uses less digits than its factorization.
136004123140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2621 (or 2619 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 136004123140 its reverse (41321400631), we get a palindrome (177325523771).
The spelling of 136004123140 in words is "one hundred thirty-six billion, four million, one hundred twenty-three thousand, one hundred forty".
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