Base | Representation |
---|---|
bin | 11001010101111000… |
… | …10011100100001111 |
3 | 1022010011212120200111 |
4 | 30222330103210033 |
5 | 210330432304433 |
6 | 10130013540451 |
7 | 661103412232 |
oct | 145274234417 |
9 | 38104776614 |
10 | 13605353743 |
11 | 585195a703 |
12 | 27784a4727 |
13 | 138a923397 |
14 | 930d07419 |
15 | 54967adcd |
hex | 32af1390f |
13605353743 has 2 divisors, whose sum is σ = 13605353744. Its totient is φ = 13605353742.
The previous prime is 13605353719. The next prime is 13605353761. The reversal of 13605353743 is 34735350631.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13605353743 - 221 = 13603256591 is a prime.
It is a super-2 number, since 2×136053537432 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13605353696 and 13605353705.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13605353143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6802676871 + 6802676872.
It is an arithmetic number, because the mean of its divisors is an integer number (6802676872).
Almost surely, 213605353743 is an apocalyptic number.
13605353743 is a deficient number, since it is larger than the sum of its proper divisors (1).
13605353743 is an equidigital number, since it uses as much as digits as its factorization.
13605353743 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 340200, while the sum is 40.
The spelling of 13605353743 in words is "thirteen billion, six hundred five million, three hundred fifty-three thousand, seven hundred forty-three".
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