Base | Representation |
---|---|
bin | 11001010110000001… |
… | …01111000110110001 |
3 | 1022010021001120210111 |
4 | 30223000233012301 |
5 | 210331231440441 |
6 | 10130054501321 |
7 | 661116320203 |
oct | 145300570661 |
9 | 38107046714 |
10 | 13606515121 |
11 | 5852583221 |
12 | 2778964841 |
13 | 138ac3bba4 |
14 | 93112a773 |
15 | 54980a081 |
hex | 32b02f1b1 |
13606515121 has 2 divisors, whose sum is σ = 13606515122. Its totient is φ = 13606515120.
The previous prime is 13606515119. The next prime is 13606515127. The reversal of 13606515121 is 12151560631.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12003393600 + 1603121521 = 109560^2 + 40039^2 .
It is a cyclic number.
It is not a de Polignac number, because 13606515121 - 21 = 13606515119 is a prime.
Together with 13606515119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13606515127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6803257560 + 6803257561.
It is an arithmetic number, because the mean of its divisors is an integer number (6803257561).
Almost surely, 213606515121 is an apocalyptic number.
It is an amenable number.
13606515121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13606515121 is an equidigital number, since it uses as much as digits as its factorization.
13606515121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 13606515121 in words is "thirteen billion, six hundred six million, five hundred fifteen thousand, one hundred twenty-one".
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