1360720114493 has 2 divisors, whose sum is σ = 1360720114494. Its totient is φ = 1360720114492.

The previous prime is 1360720114487. The next prime is 1360720114499. The reversal of 1360720114493 is 3944110270631.

It is a balanced prime because it is at equal distance from previous prime (1360720114487) and next prime (1360720114499).

It can be written as a sum of positive squares in only one way, i.e., 1104439151929 + 256280962564 = 1050923^2 + 506242^2 .

It is a cyclic number.

It is not a de Polignac number, because 1360720114493 - 2¹⁴ = 1360720098109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1360720114493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1360720114499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680360057246 + 680360057247.

It is an arithmetic number, because the mean of its divisors is an integer number (680360057247).

Almost surely, 2^{1360720114493} is an apocalyptic number.

It is an amenable number.

1360720114493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360720114493 is an equidigital number, since it uses as much as digits as its factorization.

1360720114493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108864, while the sum is 41.

The spelling of 1360720114493 in words is "one trillion, three hundred sixty billion, seven hundred twenty million, one hundred fourteen thousand, four hundred ninety-three".