136110450244841 has 2 divisors, whose sum is σ = 136110450244842. Its totient is φ = 136110450244840.

The previous prime is 136110450244789. The next prime is 136110450244843. The reversal of 136110450244841 is 148442054011631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79561494075625 + 56548956169216 = 8919725^2 + 7519904^2 .

It is a cyclic number.

It is not a de Polignac number, because 136110450244841 - 2⁶ = 136110450244777 is a prime.

Together with 136110450244843, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 136110450244792 and 136110450244801.

It is not a weakly prime, because it can be changed into another prime (136110450244843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68055225122420 + 68055225122421.

It is an arithmetic number, because the mean of its divisors is an integer number (68055225122421).

Almost surely, 2^{136110450244841} is an apocalyptic number.

It is an amenable number.

136110450244841 is a deficient number, since it is larger than the sum of its proper divisors (1).

136110450244841 is an equidigital number, since it uses as much as digits as its factorization.

136110450244841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 368640, while the sum is 44.

The spelling of 136110450244841 in words is "one hundred thirty-six trillion, one hundred ten billion, four hundred fifty million, two hundred forty-four thousand, eight hundred forty-one".