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136110450244843 is a prime number
BaseRepresentation
bin11110111100101010101111…
…000010010111110011101011
3122211221000212022011121212001
4132330222233002113303223
5120320013200230313333
61201252135545031431
740445440561622404
oct3674525702276353
9584830768147761
10136110450244843
113a407132853368
121332314a485577
135ac4211496139
142587ad0c949ab
1510b0829e14b7d
hex7bcaaf097ceb

136110450244843 has 2 divisors, whose sum is σ = 136110450244844. Its totient is φ = 136110450244842.

The previous prime is 136110450244841. The next prime is 136110450244907. The reversal of 136110450244843 is 348442054011631.

It is a weak prime.

It is an emirp because it is prime and its reverse (348442054011631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136110450244843 - 21 = 136110450244841 is a prime.

Together with 136110450244841, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 136110450244793 and 136110450244802.

It is not a weakly prime, because it can be changed into another prime (136110450244841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68055225122421 + 68055225122422.

It is an arithmetic number, because the mean of its divisors is an integer number (68055225122422).

Almost surely, 2136110450244843 is an apocalyptic number.

136110450244843 is a deficient number, since it is larger than the sum of its proper divisors (1).

136110450244843 is an equidigital number, since it uses as much as digits as its factorization.

136110450244843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1105920, while the sum is 46.

The spelling of 136110450244843 in words is "one hundred thirty-six trillion, one hundred ten billion, four hundred fifty million, two hundred forty-four thousand, eight hundred forty-three".