Base | Representation |
---|---|
bin | 11110111100101010101111… |
… | …000010010111110100101011 |
3 | 122211221000212022011121221102 |
4 | 132330222233002113310223 |
5 | 120320013200230314112 |
6 | 1201252135545032015 |
7 | 40445440561622525 |
oct | 3674525702276453 |
9 | 584830768147842 |
10 | 136110450244907 |
11 | 3a407132853416 |
12 | 1332314a48560b |
13 | 5ac4211496188 |
14 | 2587ad0c94a15 |
15 | 10b0829e14bc2 |
hex | 7bcaaf097d2b |
136110450244907 has 2 divisors, whose sum is σ = 136110450244908. Its totient is φ = 136110450244906.
The previous prime is 136110450244843. The next prime is 136110450244919. The reversal of 136110450244907 is 709442054011631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136110450244907 - 26 = 136110450244843 is a prime.
It is not a weakly prime, because it can be changed into another prime (136110450244957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68055225122453 + 68055225122454.
It is an arithmetic number, because the mean of its divisors is an integer number (68055225122454).
Almost surely, 2136110450244907 is an apocalyptic number.
136110450244907 is a deficient number, since it is larger than the sum of its proper divisors (1).
136110450244907 is an equidigital number, since it uses as much as digits as its factorization.
136110450244907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 136110450244907 in words is "one hundred thirty-six trillion, one hundred ten billion, four hundred fifty million, two hundred forty-four thousand, nine hundred seven".
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