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136125417301 is a prime number
BaseRepresentation
bin111111011000110110…
…1010000011101010101
3111000100210222200111021
41332301231100131111
54212241101323201
6142311332041141
712556212645556
oct1766155203525
9430323880437
10136125417301
1152804281885
12224701631b1
13cab4c43203
146834c0432d
15381a9c1ea1
hex1fb1b50755

136125417301 has 2 divisors, whose sum is σ = 136125417302. Its totient is φ = 136125417300.

The previous prime is 136125417271. The next prime is 136125417367. The reversal of 136125417301 is 103714521631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132386094801 + 3739322500 = 363849^2 + 61150^2 .

It is a cyclic number.

It is not a de Polignac number, because 136125417301 - 211 = 136125415253 is a prime.

It is a super-3 number, since 3×1361254173013 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136125417101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68062708650 + 68062708651.

It is an arithmetic number, because the mean of its divisors is an integer number (68062708651).

Almost surely, 2136125417301 is an apocalyptic number.

It is an amenable number.

136125417301 is a deficient number, since it is larger than the sum of its proper divisors (1).

136125417301 is an equidigital number, since it uses as much as digits as its factorization.

136125417301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 136125417301 its reverse (103714521631), we get a palindrome (239839938932).

The spelling of 136125417301 in words is "one hundred thirty-six billion, one hundred twenty-five million, four hundred seventeen thousand, three hundred one".