Base | Representation |
---|---|
bin | 10011110011110001000… |
… | …100100100100111001011 |
3 | 11211010122010212212002002 |
4 | 103303301010210213023 |
5 | 134300322032020011 |
6 | 2521203533101215 |
7 | 200230101362456 |
oct | 23636104444713 |
9 | 4733563785062 |
10 | 1361254173131 |
11 | 485339547076 |
12 | 19b9a132780b |
13 | 9b49a6357b8 |
14 | 49c5683049d |
15 | 25621814c3b |
hex | 13cf11249cb |
1361254173131 has 2 divisors, whose sum is σ = 1361254173132. Its totient is φ = 1361254173130.
The previous prime is 1361254173107. The next prime is 1361254173151. The reversal of 1361254173131 is 1313714521631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1361254173131 - 222 = 1361249978827 is a prime.
It is a super-2 number, since 2×13612541731312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1361254173151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680627086565 + 680627086566.
It is an arithmetic number, because the mean of its divisors is an integer number (680627086566).
Almost surely, 21361254173131 is an apocalyptic number.
1361254173131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361254173131 is an equidigital number, since it uses as much as digits as its factorization.
1361254173131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 45360, while the sum is 38.
Adding to 1361254173131 its reverse (1313714521631), we get a palindrome (2674968694762).
The spelling of 1361254173131 in words is "one trillion, three hundred sixty-one billion, two hundred fifty-four million, one hundred seventy-three thousand, one hundred thirty-one".
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