Base | Representation |
---|---|
bin | 10000001110101… |
… | …11101011100101 |
3 | 100111012010022201 |
4 | 20013113223211 |
5 | 234323242413 |
6 | 21302054501 |
7 | 3242152666 |
oct | 1007275345 |
9 | 314163281 |
10 | 136149733 |
11 | 6a942345 |
12 | 3971a431 |
13 | 2228c995 |
14 | 1412136d |
15 | be459dd |
hex | 81d7ae5 |
136149733 has 2 divisors, whose sum is σ = 136149734. Its totient is φ = 136149732.
The previous prime is 136149731. The next prime is 136149779. The reversal of 136149733 is 337941631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130919364 + 5230369 = 11442^2 + 2287^2 .
It is a cyclic number.
It is not a de Polignac number, because 136149733 - 21 = 136149731 is a prime.
It is a super-4 number, since 4×1361497334 (a number of 34 digits) contains 4444 as substring.
Together with 136149731, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 136149692 and 136149701.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136149731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68074866 + 68074867.
It is an arithmetic number, because the mean of its divisors is an integer number (68074867).
Almost surely, 2136149733 is an apocalyptic number.
It is an amenable number.
136149733 is a deficient number, since it is larger than the sum of its proper divisors (1).
136149733 is an equidigital number, since it uses as much as digits as its factorization.
136149733 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 40824, while the sum is 37.
The square root of 136149733 is about 11668.3217730743. The cubic root of 136149733 is about 514.4449771995. Note that the first 3 decimals are identical.
The spelling of 136149733 in words is "one hundred thirty-six million, one hundred forty-nine thousand, seven hundred thirty-three".
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