Base | Representation |
---|---|
bin | 10011110011111111111… |
… | …101101010001111001001 |
3 | 11211011021120000100201122 |
4 | 103303333331222033021 |
5 | 134301330012110101 |
6 | 2521244420125025 |
7 | 200236224134321 |
oct | 23637775521711 |
9 | 4734246010648 |
10 | 1361504019401 |
11 | 485457585299 |
12 | 19ba50b36775 |
13 | 9b50a323226 |
14 | 49c7baaa281 |
15 | 2563871851b |
hex | 13cfff6a3c9 |
1361504019401 has 2 divisors, whose sum is σ = 1361504019402. Its totient is φ = 1361504019400.
The previous prime is 1361504019383. The next prime is 1361504019431. The reversal of 1361504019401 is 1049104051631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1105650147001 + 255853872400 = 1051499^2 + 505820^2 .
It is a cyclic number.
It is not a de Polignac number, because 1361504019401 - 222 = 1361499825097 is a prime.
It is not a weakly prime, because it can be changed into another prime (1361504019431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680752009700 + 680752009701.
It is an arithmetic number, because the mean of its divisors is an integer number (680752009701).
Almost surely, 21361504019401 is an apocalyptic number.
It is an amenable number.
1361504019401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361504019401 is an equidigital number, since it uses as much as digits as its factorization.
1361504019401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 1361504019401 in words is "one trillion, three hundred sixty-one billion, five hundred four million, nineteen thousand, four hundred one".
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