Base | Representation |
---|---|
bin | 10011110011111111111… |
… | …101101010001111100111 |
3 | 11211011021120000100202202 |
4 | 103303333331222033213 |
5 | 134301330012110211 |
6 | 2521244420125115 |
7 | 200236224134363 |
oct | 23637775521747 |
9 | 4734246010682 |
10 | 1361504019431 |
11 | 485457585316 |
12 | 19ba50b3679b |
13 | 9b50a32324a |
14 | 49c7baaa2a3 |
15 | 2563871853b |
hex | 13cfff6a3e7 |
1361504019431 has 2 divisors, whose sum is σ = 1361504019432. Its totient is φ = 1361504019430.
The previous prime is 1361504019401. The next prime is 1361504019443. The reversal of 1361504019431 is 1349104051631.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1361504019431 is a prime.
It is a super-2 number, since 2×13615040194312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361504019401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680752009715 + 680752009716.
It is an arithmetic number, because the mean of its divisors is an integer number (680752009716).
Almost surely, 21361504019431 is an apocalyptic number.
1361504019431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361504019431 is an equidigital number, since it uses as much as digits as its factorization.
1361504019431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 38.
The spelling of 1361504019431 in words is "one trillion, three hundred sixty-one billion, five hundred four million, nineteen thousand, four hundred thirty-one".
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