Base | Representation |
---|---|
bin | 10011110100011011111… |
… | …111100101101111101111 |
3 | 11211012111022220110001211 |
4 | 103310123333211233233 |
5 | 134303310404143333 |
6 | 2521403215415251 |
7 | 200253664300015 |
oct | 23643377455757 |
9 | 4735438813054 |
10 | 1361974287343 |
11 | 485678a8458a |
12 | 19bb62524527 |
13 | 9b583898297 |
14 | 49cc43228b5 |
15 | 25664b5becd |
hex | 13d1bfe5bef |
1361974287343 has 2 divisors, whose sum is σ = 1361974287344. Its totient is φ = 1361974287342.
The previous prime is 1361974287341. The next prime is 1361974287353. The reversal of 1361974287343 is 3437824791631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1361974287343 - 21 = 1361974287341 is a prime.
Together with 1361974287341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361974287341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680987143671 + 680987143672.
It is an arithmetic number, because the mean of its divisors is an integer number (680987143672).
Almost surely, 21361974287343 is an apocalyptic number.
1361974287343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361974287343 is an equidigital number, since it uses as much as digits as its factorization.
1361974287343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18289152, while the sum is 58.
The spelling of 1361974287343 in words is "one trillion, three hundred sixty-one billion, nine hundred seventy-four million, two hundred eighty-seven thousand, three hundred forty-three".
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