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1362114355013 is a prime number
BaseRepresentation
bin10011110100100100010…
…101111001111101000101
311211012212002110121210022
4103310210111321331011
5134304102233330023
62521425141504525
7200260314661406
oct23644425717505
94735762417708
101362114355013
11485740052495
1219bba1412145
139b5a68ca369
1449cd8b839ad
15256720c87c8
hex13d24579f45

1362114355013 has 2 divisors, whose sum is σ = 1362114355014. Its totient is φ = 1362114355012.

The previous prime is 1362114354967. The next prime is 1362114355037. The reversal of 1362114355013 is 3105534112631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 927382482049 + 434731872964 = 963007^2 + 659342^2 .

It is an emirp because it is prime and its reverse (3105534112631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1362114355013 - 26 = 1362114354949 is a prime.

It is a super-2 number, since 2×13621143550132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1362114355073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681057177506 + 681057177507.

It is an arithmetic number, because the mean of its divisors is an integer number (681057177507).

Almost surely, 21362114355013 is an apocalyptic number.

It is an amenable number.

1362114355013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1362114355013 is an equidigital number, since it uses as much as digits as its factorization.

1362114355013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 1362114355013 its reverse (3105534112631), we get a palindrome (4467648467644).

The spelling of 1362114355013 in words is "one trillion, three hundred sixty-two billion, one hundred fourteen million, three hundred fifty-five thousand, thirteen".