1362114355037 has 2 divisors, whose sum is σ = 1362114355038. Its totient is φ = 1362114355036.

The previous prime is 1362114355013. The next prime is 1362114355039. The reversal of 1362114355037 is 7305534112631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 931744242361 + 430370112676 = 965269^2 + 656026^2 .

It is a cyclic number.

It is not a de Polignac number, because 1362114355037 - 2¹⁴ = 1362114338653 is a prime.

Together with 1362114355039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1362114354985 and 1362114355003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1362114355039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681057177518 + 681057177519.

It is an arithmetic number, because the mean of its divisors is an integer number (681057177519).

Almost surely, 2^{1362114355037} is an apocalyptic number.

It is an amenable number.

1362114355037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1362114355037 is an equidigital number, since it uses as much as digits as its factorization.

1362114355037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 41.

Adding to 1362114355037 its reverse (7305534112631), we get a palindrome (8667648467668).

The spelling of 1362114355037 in words is "one trillion, three hundred sixty-two billion, one hundred fourteen million, three hundred fifty-five thousand, thirty-seven".