Base | Representation |
---|---|
bin | 10011110100100100100… |
… | …001101000111100001010 |
3 | 11211012212022020220022121 |
4 | 103310210201220330022 |
5 | 134304104030243200 |
6 | 2521425331441454 |
7 | 200260353062425 |
oct | 23644441507412 |
9 | 4735768226277 |
10 | 1362117431050 |
11 | 485741863572 |
12 | 19bba245628a |
13 | 9b5a74364bc |
14 | 49cd93449bc |
15 | 256724d4e1a |
hex | 13d24868f0a |
1362117431050 has 48 divisors (see below), whose sum is σ = 2570886827712. Its totient is φ = 536825004800.
The previous prime is 1362117430969. The next prime is 1362117431053. The reversal of 1362117431050 is 501347112631.
It is a junction number, because it is equal to n+sod(n) for n = 1362117430997 and 1362117431015.
It is not an unprimeable number, because it can be changed into a prime (1362117431053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5389617 + ... + 5636683.
It is an arithmetic number, because the mean of its divisors is an integer number (53560142244).
Almost surely, 21362117431050 is an apocalyptic number.
1362117431050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1362117431050 is a deficient number, since it is larger than the sum of its proper divisors (1208769396662).
1362117431050 is a wasteful number, since it uses less digits than its factorization.
1362117431050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248703 (or 248698 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 1362117431050 in words is "one trillion, three hundred sixty-two billion, one hundred seventeen million, four hundred thirty-one thousand, fifty".
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