Base | Representation |
---|---|
bin | 111111011011100100… |
… | …0111000000001000101 |
3 | 111000121011110100212022 |
4 | 1332313020320001011 |
5 | 4212432413341201 |
6 | 142324345132525 |
7 | 12561400341206 |
oct | 1766710700105 |
9 | 430534410768 |
10 | 136216543301 |
11 | 52850762123 |
12 | 2249678a145 |
13 | cacaa9a817 |
14 | 6842d655ad |
15 | 38239c241b |
hex | 1fb7238045 |
136216543301 has 2 divisors, whose sum is σ = 136216543302. Its totient is φ = 136216543300.
The previous prime is 136216543237. The next prime is 136216543303. The reversal of 136216543301 is 103345612631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93774363076 + 42442180225 = 306226^2 + 206015^2 .
It is a cyclic number.
It is not a de Polignac number, because 136216543301 - 26 = 136216543237 is a prime.
Together with 136216543303, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136216543303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68108271650 + 68108271651.
It is an arithmetic number, because the mean of its divisors is an integer number (68108271651).
Almost surely, 2136216543301 is an apocalyptic number.
It is an amenable number.
136216543301 is a deficient number, since it is larger than the sum of its proper divisors (1).
136216543301 is an equidigital number, since it uses as much as digits as its factorization.
136216543301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 35.
The spelling of 136216543301 in words is "one hundred thirty-six billion, two hundred sixteen million, five hundred forty-three thousand, three hundred one".
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