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13625442641 is a prime number
BaseRepresentation
bin11001011000010001…
…11100000101010001
31022011120200012110202
430230020330011101
5210401103131031
610132012304545
7661436231366
oct145410740521
938146605422
1013625442641
1158622307a8
122783172155
131391b380c5
1493385646d
1554b2e82cb
hex32c23c151

13625442641 has 2 divisors, whose sum is σ = 13625442642. Its totient is φ = 13625442640.

The previous prime is 13625442587. The next prime is 13625442643. The reversal of 13625442641 is 14624452631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13530575041 + 94867600 = 116321^2 + 9740^2 .

It is a cyclic number.

It is not a de Polignac number, because 13625442641 - 26 = 13625442577 is a prime.

Together with 13625442643, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13625442595 and 13625442604.

It is not a weakly prime, because it can be changed into another prime (13625442643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6812721320 + 6812721321.

It is an arithmetic number, because the mean of its divisors is an integer number (6812721321).

Almost surely, 213625442641 is an apocalyptic number.

It is an amenable number.

13625442641 is a deficient number, since it is larger than the sum of its proper divisors (1).

13625442641 is an equidigital number, since it uses as much as digits as its factorization.

13625442641 is an evil number, because the sum of its binary digits is even.

The product of its digits is 138240, while the sum is 38.

The spelling of 13625442641 in words is "thirteen billion, six hundred twenty-five million, four hundred forty-two thousand, six hundred forty-one".