Base | Representation |
---|---|
bin | 11110111111101000111001… |
… | …010110000110001001010100 |
3 | 122212122112220020011220102211 |
4 | 132333220321112012021110 |
5 | 120331334332314242400 |
6 | 1201530024534243204 |
7 | 40466256465220312 |
oct | 3677507126061124 |
9 | 585575806156384 |
10 | 136314634134100 |
11 | 3a485791287484 |
12 | 133568331b6504 |
13 | 5b0a55153cc16 |
14 | 25939408b70b2 |
15 | 10b5cca834dba |
hex | 7bfa39586254 |
136314634134100 has 36 divisors (see below), whose sum is σ = 299547094772800. Its totient is φ = 53835652971360.
The previous prime is 136314634134073. The next prime is 136314634134163. The reversal of 136314634134100 is 1431436413631.
It is a super-2 number, since 2×1363146341341002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8627500590 + ... + 8627516389.
Almost surely, 2136314634134100 is an apocalyptic number.
136314634134100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
136314634134100 is an abundant number, since it is smaller than the sum of its proper divisors (163232460638700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136314634134100 is a wasteful number, since it uses less digits than its factorization.
136314634134100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17255017072 (or 17255017065 counting only the distinct ones).
The product of its (nonzero) digits is 186624, while the sum is 40.
The spelling of 136314634134100 in words is "one hundred thirty-six trillion, three hundred fourteen billion, six hundred thirty-four million, one hundred thirty-four thousand, one hundred".
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