Base | Representation |
---|---|
bin | 111111011111000000… |
… | …1110010010100111100 |
3 | 111000220012221112211111 |
4 | 1332332001302110330 |
5 | 4213202011004000 |
6 | 142344034331404 |
7 | 12564302642434 |
oct | 1767601622474 |
9 | 430805845744 |
10 | 136332125500 |
11 | 528aaa267aa |
12 | 22509429b64 |
13 | cb18a0895c |
14 | 68544512c4 |
15 | 382dc03cba |
hex | 1fbe07253c |
136332125500 has 48 divisors (see below), whose sum is σ = 307354215168. Its totient is φ = 52773720000.
The previous prime is 136332125477. The next prime is 136332125599. The reversal of 136332125500 is 5521233631.
It is a super-3 number, since 3×1363321255003 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4382311 + ... + 4413310.
It is an arithmetic number, because the mean of its divisors is an integer number (6403212816).
Almost surely, 2136332125500 is an apocalyptic number.
136332125500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
136332125500 is an abundant number, since it is smaller than the sum of its proper divisors (171022089668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136332125500 is a wasteful number, since it uses less digits than its factorization.
136332125500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8795671 (or 8795659 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 31.
The spelling of 136332125500 in words is "one hundred thirty-six billion, three hundred thirty-two million, one hundred twenty-five thousand, five hundred".
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