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136340033321477 is a prime number
BaseRepresentation
bin11111000000000000100011…
…010000010011101000000101
3122212201222110100020022101102
4133000000203100103220011
5120332243342012241402
61201545425135105445
740501146060600266
oct3700004320235005
9585658410208342
10136340033321477
113a495535483927
121335b741372285
135b0ca6b691b8b
142594c6dc9296d
1510b67b55aa102
hex7c0023413a05

136340033321477 has 2 divisors, whose sum is σ = 136340033321478. Its totient is φ = 136340033321476.

The previous prime is 136340033321407. The next prime is 136340033321483. The reversal of 136340033321477 is 774123330043631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78978662356036 + 57361370965441 = 8886994^2 + 7573729^2 .

It is a cyclic number.

It is not a de Polignac number, because 136340033321477 - 212 = 136340033317381 is a prime.

It is a super-2 number, since 2×1363400333214772 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136340033321407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68170016660738 + 68170016660739.

It is an arithmetic number, because the mean of its divisors is an integer number (68170016660739).

Almost surely, 2136340033321477 is an apocalyptic number.

It is an amenable number.

136340033321477 is a deficient number, since it is larger than the sum of its proper divisors (1).

136340033321477 is an equidigital number, since it uses as much as digits as its factorization.

136340033321477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2286144, while the sum is 47.

The spelling of 136340033321477 in words is "one hundred thirty-six trillion, three hundred forty billion, thirty-three million, three hundred twenty-one thousand, four hundred seventy-seven".