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136397243557 is a prime number
BaseRepresentation
bin111111100000111101…
…0001100010010100101
3111001001202110220000101
41333001322030102211
54213320143243212
6142354322144101
712566023304131
oct1770172142245
9431052426011
10136397243557
1152933762983
12225271b2031
13cb29358353
14685cd623c1
1538347b8157
hex1fc1e8c4a5

136397243557 has 2 divisors, whose sum is σ = 136397243558. Its totient is φ = 136397243556.

The previous prime is 136397243513. The next prime is 136397243561. The reversal of 136397243557 is 755342793631.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123173623521 + 13223620036 = 350961^2 + 114994^2 .

It is an emirp because it is prime and its reverse (755342793631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136397243557 - 223 = 136388854949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 136397243498 and 136397243507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136397243057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68198621778 + 68198621779.

It is an arithmetic number, because the mean of its divisors is an integer number (68198621779).

Almost surely, 2136397243557 is an apocalyptic number.

It is an amenable number.

136397243557 is a deficient number, since it is larger than the sum of its proper divisors (1).

136397243557 is an equidigital number, since it uses as much as digits as its factorization.

136397243557 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14288400, while the sum is 55.

The spelling of 136397243557 in words is "one hundred thirty-six billion, three hundred ninety-seven million, two hundred forty-three thousand, five hundred fifty-seven".