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1364052504631 is a prime number
BaseRepresentation
bin10011110110010111110…
…111010111000000110111
311211101212011102211020111
4103312113313113000313
5134322034420122011
62522345335043451
7200356330661365
oct23662767270067
94741764384214
101364052504631
11486545094a33
121a0442510587
139b8252ca45b
144a04033c635
1525737320121
hex13d97dd7037

1364052504631 has 2 divisors, whose sum is σ = 1364052504632. Its totient is φ = 1364052504630.

The previous prime is 1364052504629. The next prime is 1364052504637.

1364052504631 is nontrivially palindromic in base 10.

It is a weak prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 1364052504631 - 21 = 1364052504629 is a prime.

It is a super-2 number, since 2×13640525046312 (a number of 25 digits) contains 22 as substring.

Together with 1364052504629, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1364052504637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682026252315 + 682026252316.

It is an arithmetic number, because the mean of its divisors is an integer number (682026252316).

Almost surely, 21364052504631 is an apocalyptic number.

1364052504631 is a deficient number, since it is larger than the sum of its proper divisors (1).

1364052504631 is an equidigital number, since it uses as much as digits as its factorization.

1364052504631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 1364052504631 in words is "one trillion, three hundred sixty-four billion, fifty-two million, five hundred four thousand, six hundred thirty-one".