Base | Representation |
---|---|
bin | 111111100001001110… |
… | …0110001110010000001 |
3 | 111001002101112111212012 |
4 | 1333002130301302001 |
5 | 4213330003410032 |
6 | 142355244342305 |
7 | 12566163335015 |
oct | 1770234616201 |
9 | 431071474765 |
10 | 136406310017 |
11 | 5293889571a |
12 | 2252a244995 |
13 | cb2b1b1013 |
14 | 6860242545 |
15 | 38354a96b2 |
hex | 1fc2731c81 |
136406310017 has 2 divisors, whose sum is σ = 136406310018. Its totient is φ = 136406310016.
The previous prime is 136406309971. The next prime is 136406310049. The reversal of 136406310017 is 710013604631.
It is an a-pointer prime, because the next prime (136406310049) can be obtained adding 136406310017 to its sum of digits (32).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129600720001 + 6805590016 = 360001^2 + 82496^2 .
It is a cyclic number.
It is not a de Polignac number, because 136406310017 - 214 = 136406293633 is a prime.
It is not a weakly prime, because it can be changed into another prime (136406312017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68203155008 + 68203155009.
It is an arithmetic number, because the mean of its divisors is an integer number (68203155009).
Almost surely, 2136406310017 is an apocalyptic number.
It is an amenable number.
136406310017 is a deficient number, since it is larger than the sum of its proper divisors (1).
136406310017 is an equidigital number, since it uses as much as digits as its factorization.
136406310017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 32.
Adding to 136406310017 its reverse (710013604631), we get a palindrome (846419914648).
The spelling of 136406310017 in words is "one hundred thirty-six billion, four hundred six million, three hundred ten thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •