Base | Representation |
---|---|
bin | 1100011010000001100111… |
… | …0110001011100100001000 |
3 | 1210022002110011001210102111 |
4 | 3012200121312023210020 |
5 | 3241444234420000030 |
6 | 45002411552312104 |
7 | 2605355612566000 |
oct | 306403166134410 |
9 | 53262404053374 |
10 | 13641249765640 |
11 | 438a2489587a2 |
12 | 1643922b42634 |
13 | 77c497595173 |
14 | 35235083d000 |
15 | 189c90aa762a |
hex | c6819d8b908 |
13641249765640 has 64 divisors (see below), whose sum is σ = 35793366768000. Its totient is φ = 4676999914944.
The previous prime is 13641249765587. The next prime is 13641249765659. The reversal of 13641249765640 is 4656794214631.
It is a happy number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 497116374 + ... + 497143813.
It is an arithmetic number, because the mean of its divisors is an integer number (559271355750).
Almost surely, 213641249765640 is an apocalyptic number.
13641249765640 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13641249765640 is an abundant number, since it is smaller than the sum of its proper divisors (22152117002360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13641249765640 is an equidigital number, since it uses as much as digits as its factorization.
13641249765640 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 994260219 (or 994260201 counting only the distinct ones).
The product of its (nonzero) digits is 26127360, while the sum is 58.
The spelling of 13641249765640 in words is "thirteen trillion, six hundred forty-one billion, two hundred forty-nine million, seven hundred sixty-five thousand, six hundred forty".
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