136423424011241 has 2 divisors, whose sum is σ = 136423424011242. Its totient is φ = 136423424011240.

The previous prime is 136423424011169. The next prime is 136423424011279. The reversal of 136423424011241 is 142110424324631.

It is an a-pointer prime, because the next prime (136423424011279) can be obtained adding 136423424011241 to its sum of digits (38).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136413733577641 + 9690433600 = 11679629^2 + 98440^2 .

It is a cyclic number.

It is not a de Polignac number, because 136423424011241 - 2¹⁴ = 136423423994857 is a prime.

It is a super-2 number, since 2×136423424011241² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 136423424011195 and 136423424011204.

It is not a weakly prime, because it can be changed into another prime (136423424011841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68211712005620 + 68211712005621.

It is an arithmetic number, because the mean of its divisors is an integer number (68211712005621).

Almost surely, 2^{136423424011241} is an apocalyptic number.

It is an amenable number.

136423424011241 is a deficient number, since it is larger than the sum of its proper divisors (1).

136423424011241 is an equidigital number, since it uses as much as digits as its factorization.

136423424011241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 110592, while the sum is 38.

Adding to 136423424011241 its reverse (142110424324631), we get a palindrome (278533848335872).

The spelling of 136423424011241 in words is "one hundred thirty-six trillion, four hundred twenty-three billion, four hundred twenty-four million, eleven thousand, two hundred forty-one".