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136423424076677 is a prime number
BaseRepresentation
bin11111000001001110001101…
…101110110010101110000101
3122220000221200222122121002022
4133001032031232302232011
5120340130133030423202
61202052020020252525
740510160424403463
oct3701161556625605
9586027628577068
10136423424076677
113a517938381531
1213373934841145
135b1789b1338ca
142598d010ad833
1510b8a465a6ea2
hex7c138dbb2b85

136423424076677 has 2 divisors, whose sum is σ = 136423424076678. Its totient is φ = 136423424076676.

The previous prime is 136423424076623. The next prime is 136423424076707. The reversal of 136423424076677 is 776670424324631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76624970237761 + 59798453838916 = 8753569^2 + 7732946^2 .

It is a cyclic number.

It is not a de Polignac number, because 136423424076677 - 26 = 136423424076613 is a prime.

It is a super-2 number, since 2×1364234240766772 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136423424006677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68211712038338 + 68211712038339.

It is an arithmetic number, because the mean of its divisors is an integer number (68211712038339).

Almost surely, 2136423424076677 is an apocalyptic number.

It is an amenable number.

136423424076677 is a deficient number, since it is larger than the sum of its proper divisors (1).

136423424076677 is an equidigital number, since it uses as much as digits as its factorization.

136423424076677 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170698752, while the sum is 62.

The spelling of 136423424076677 in words is "one hundred thirty-six trillion, four hundred twenty-three billion, four hundred twenty-four million, seventy-six thousand, six hundred seventy-seven".