Base | Representation |
---|---|
bin | 11111000001001110001101… |
… | …101110110010101110100011 |
3 | 122220000221200222122121010102 |
4 | 133001032031232302232203 |
5 | 120340130133030423312 |
6 | 1202052020020253015 |
7 | 40510160424403535 |
oct | 3701161556625643 |
9 | 586027628577112 |
10 | 136423424076707 |
11 | 3a517938381559 |
12 | 1337393484116b |
13 | 5b1789b133921 |
14 | 2598d010ad855 |
15 | 10b8a465a6ec2 |
hex | 7c138dbb2ba3 |
136423424076707 has 2 divisors, whose sum is σ = 136423424076708. Its totient is φ = 136423424076706.
The previous prime is 136423424076677. The next prime is 136423424076781. The reversal of 136423424076707 is 707670424324631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 136423424076707 - 210 = 136423424075683 is a prime.
It is a super-2 number, since 2×1364234240767072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (136423424076007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68211712038353 + 68211712038354.
It is an arithmetic number, because the mean of its divisors is an integer number (68211712038354).
Almost surely, 2136423424076707 is an apocalyptic number.
136423424076707 is a deficient number, since it is larger than the sum of its proper divisors (1).
136423424076707 is an equidigital number, since it uses as much as digits as its factorization.
136423424076707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28449792, while the sum is 56.
The spelling of 136423424076707 in words is "one hundred thirty-six trillion, four hundred twenty-three billion, four hundred twenty-four million, seventy-six thousand, seven hundred seven".
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