Base | Representation |
---|---|
bin | 1100011010001101110110… |
… | …1100000101010101001000 |
3 | 1210022101221010200000010221 |
4 | 3012203131230011111020 |
5 | 3242023002033444000 |
6 | 45004114004115424 |
7 | 2605533210510304 |
oct | 306433554052510 |
9 | 53271833600127 |
10 | 13644535453000 |
11 | 43906846072a1 |
12 | 164449b395b74 |
13 | 77c89c20597a |
14 | 352582d70d04 |
15 | 189dd427e61a |
hex | c68ddb05548 |
13644535453000 has 32 divisors (see below), whose sum is σ = 31928212962360. Its totient is φ = 5457814180800.
The previous prime is 13644535452997. The next prime is 13644535453001. The reversal of 13644535453000 is 35453544631.
It can be written as a sum of positive squares in 4 ways, for example, as 2457263164356 + 11187272288644 = 1567566^2 + 3344738^2 .
It is not an unprimeable number, because it can be changed into a prime (13644535453001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6822266727 + ... + 6822268726.
Almost surely, 213644535453000 is an apocalyptic number.
13644535453000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13644535453000 is an abundant number, since it is smaller than the sum of its proper divisors (18283677509360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13644535453000 is a wasteful number, since it uses less digits than its factorization.
13644535453000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13644535474 (or 13644535460 counting only the distinct ones).
The product of its (nonzero) digits is 1296000, while the sum is 43.
Adding to 13644535453000 its reverse (35453544631), we get a palindrome (13679988997631).
The spelling of 13644535453000 in words is "thirteen trillion, six hundred forty-four billion, five hundred thirty-five million, four hundred fifty-three thousand".
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