Base | Representation |
---|---|
bin | 11001011011000000… |
… | …11000100101110111 |
3 | 1022020011210211022221 |
4 | 30231200120211313 |
5 | 210422440202233 |
6 | 10134151503211 |
7 | 662135124232 |
oct | 145540304567 |
9 | 38204724287 |
10 | 13648365943 |
11 | 5874168383 |
12 | 278a987b07 |
13 | 1396802ca4 |
14 | 936902419 |
15 | 54d32542d |
hex | 32d818977 |
13648365943 has 2 divisors, whose sum is σ = 13648365944. Its totient is φ = 13648365942.
The previous prime is 13648365917. The next prime is 13648365947. The reversal of 13648365943 is 34956384631.
It is a happy number.
13648365943 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13648365943 - 25 = 13648365911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13648365947) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6824182971 + 6824182972.
It is an arithmetic number, because the mean of its divisors is an integer number (6824182972).
Almost surely, 213648365943 is an apocalyptic number.
13648365943 is a deficient number, since it is larger than the sum of its proper divisors (1).
13648365943 is an equidigital number, since it uses as much as digits as its factorization.
13648365943 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5598720, while the sum is 52.
The spelling of 13648365943 in words is "thirteen billion, six hundred forty-eight million, three hundred sixty-five thousand, nine hundred forty-three".
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