Base | Representation |
---|---|
bin | 11001011011001001… |
… | …10001010011011011 |
3 | 1022020020222020112222 |
4 | 30231210301103123 |
5 | 210423234000424 |
6 | 10134232254255 |
7 | 662150653346 |
oct | 145544612333 |
9 | 38206866488 |
10 | 13649515739 |
11 | 5874883222 |
12 | 278b24138b |
13 | 1396b16442 |
14 | 936b2145d |
15 | 54d4a0e5e |
hex | 32d9314db |
13649515739 has 2 divisors, whose sum is σ = 13649515740. Its totient is φ = 13649515738.
The previous prime is 13649515721. The next prime is 13649515741. The reversal of 13649515739 is 93751594631.
It is a strong prime.
It is an emirp because it is prime and its reverse (93751594631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13649515739 is a prime.
It is a super-2 number, since 2×136495157392 (a number of 21 digits) contains 22 as substring.
Together with 13649515741, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13649511739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6824757869 + 6824757870.
It is an arithmetic number, because the mean of its divisors is an integer number (6824757870).
Almost surely, 213649515739 is an apocalyptic number.
13649515739 is a deficient number, since it is larger than the sum of its proper divisors (1).
13649515739 is an equidigital number, since it uses as much as digits as its factorization.
13649515739 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3061800, while the sum is 53.
The spelling of 13649515739 in words is "thirteen billion, six hundred forty-nine million, five hundred fifteen thousand, seven hundred thirty-nine".
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