Base | Representation |
---|---|
bin | 10000010001011… |
… | …11101010010001 |
3 | 100111212102122112 |
4 | 20020233222101 |
5 | 234421310342 |
6 | 21313515105 |
7 | 3245213423 |
oct | 1010575221 |
9 | 314772575 |
10 | 136510097 |
11 | 70069069 |
12 | 39872a95 |
13 | 22387a09 |
14 | 141b6813 |
15 | beb7682 |
hex | 822fa91 |
136510097 has 2 divisors, whose sum is σ = 136510098. Its totient is φ = 136510096.
The previous prime is 136510091. The next prime is 136510103. The reversal of 136510097 is 790015631.
It is a balanced prime because it is at equal distance from previous prime (136510091) and next prime (136510103).
It can be written as a sum of positive squares in only one way, i.e., 77281681 + 59228416 = 8791^2 + 7696^2 .
It is an emirp because it is prime and its reverse (790015631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136510097 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (136510091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68255048 + 68255049.
It is an arithmetic number, because the mean of its divisors is an integer number (68255049).
Almost surely, 2136510097 is an apocalyptic number.
It is an amenable number.
136510097 is a deficient number, since it is larger than the sum of its proper divisors (1).
136510097 is an equidigital number, since it uses as much as digits as its factorization.
136510097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5670, while the sum is 32.
The square root of 136510097 is about 11683.7535492666. The cubic root of 136510097 is about 514.8984586308.
The spelling of 136510097 in words is "one hundred thirty-six million, five hundred ten thousand, ninety-seven".
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