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136513847 is a prime number
BaseRepresentation
bin10000010001100…
…00100100110111
3100111212121210102
420020300210313
5234421420342
621313544315
73245230361
oct1010604467
9314777712
10136513847
1170070968
123987509b
1322389632
14141b7d31
15beb8832
hex8230937

136513847 has 2 divisors, whose sum is σ = 136513848. Its totient is φ = 136513846.

The previous prime is 136513837. The next prime is 136513873. The reversal of 136513847 is 748315631.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 136513847 - 28 = 136513591 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 136513847.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136513837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68256923 + 68256924.

It is an arithmetic number, because the mean of its divisors is an integer number (68256924).

Almost surely, 2136513847 is an apocalyptic number.

136513847 is a deficient number, since it is larger than the sum of its proper divisors (1).

136513847 is an equidigital number, since it uses as much as digits as its factorization.

136513847 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60480, while the sum is 38.

The square root of 136513847 is about 11683.9140274139. The cubic root of 136513847 is about 514.9031734263.

It can be divided in two parts, 136513 and 847, that multiplied together give a palindrome (115626511).

The spelling of 136513847 in words is "one hundred thirty-six million, five hundred thirteen thousand, eight hundred forty-seven".