136544027 has 2 divisors, whose sum is σ = 136544028. Its totient is φ = 136544026.

The previous prime is 136544011. The next prime is 136544029. The reversal of 136544027 is 720445631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 136544027 - 2⁴ = 136544011 is a prime.

Together with 136544029, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 136543984 and 136544002.

It is not a weakly prime, because it can be changed into another prime (136544029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68272013 + 68272014.

It is an arithmetic number, because the mean of its divisors is an integer number (68272014).

Almost surely, 2^136544027 is an apocalyptic number.

136544027 is a deficient number, since it is larger than the sum of its proper divisors (1).

136544027 is an equidigital number, since it uses as much as digits as its factorization.

136544027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 32.

The square root of 136544027 is about 11685.2054753008. The cubic root of 136544027 is about 514.9411149565.

Adding to 136544027 its reverse (720445631), we get a palindrome (856989658).

The spelling of 136544027 in words is "one hundred thirty-six million, five hundred forty-four thousand, twenty-seven".