Base | Representation |
---|---|
bin | 111111100111000100… |
… | …0101111010100100011 |
3 | 111001121001111002022122 |
4 | 1333032020233110203 |
5 | 4214230202234101 |
6 | 142430531054455 |
7 | 12604064050166 |
oct | 1771610572443 |
9 | 431531432278 |
10 | 136602383651 |
11 | 52a29536748 |
12 | 22583a4142b |
13 | cb5c9c2116 |
14 | 687c2c1add |
15 | 38477da51b |
hex | 1fce22f523 |
136602383651 has 2 divisors, whose sum is σ = 136602383652. Its totient is φ = 136602383650.
The previous prime is 136602383461. The next prime is 136602383653. The reversal of 136602383651 is 156383206631.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (156383206631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136602383651 - 226 = 136535274787 is a prime.
It is a super-2 number, since 2×1366023836512 (a number of 23 digits) contains 22 as substring.
Together with 136602383653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (136602383653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68301191825 + 68301191826.
It is an arithmetic number, because the mean of its divisors is an integer number (68301191826).
Almost surely, 2136602383651 is an apocalyptic number.
136602383651 is a deficient number, since it is larger than the sum of its proper divisors (1).
136602383651 is an equidigital number, since it uses as much as digits as its factorization.
136602383651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 44.
The spelling of 136602383651 in words is "one hundred thirty-six billion, six hundred two million, three hundred eighty-three thousand, six hundred fifty-one".
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