Search a number
-
+
13663214065981 is a prime number
BaseRepresentation
bin1100011011010011011100…
…0001010101100100111101
31210101012010212202212011201
43012310313001111210331
53242324230300102411
645020443251415501
72610064116220024
oct306646701254475
953335125685151
1013663214065981
11439859a160727
1216480328b4591
13781587bc7a9c
143534359698bb
1518a628ed33c1
hexc6d3705593d

13663214065981 has 2 divisors, whose sum is σ = 13663214065982. Its totient is φ = 13663214065980.

The previous prime is 13663214065927. The next prime is 13663214066053. The reversal of 13663214065981 is 18956041236631.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11238357797956 + 2424856268025 = 3352366^2 + 1557195^2 .

It is a cyclic number.

It is not a de Polignac number, because 13663214065981 - 221 = 13663211968829 is a prime.

It is a super-2 number, since 2×136632140659812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13663214065381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6831607032990 + 6831607032991.

It is an arithmetic number, because the mean of its divisors is an integer number (6831607032991).

Almost surely, 213663214065981 is an apocalyptic number.

It is an amenable number.

13663214065981 is a deficient number, since it is larger than the sum of its proper divisors (1).

13663214065981 is an equidigital number, since it uses as much as digits as its factorization.

13663214065981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5598720, while the sum is 55.

The spelling of 13663214065981 in words is "thirteen trillion, six hundred sixty-three billion, two hundred fourteen million, sixty-five thousand, nine hundred eighty-one".