Base | Representation |
---|---|
bin | 1100011011010011110101… |
… | …1101001000110001100111 |
3 | 1210101012102101220022221211 |
4 | 3012310331131020301213 |
5 | 3242324440414014441 |
6 | 45020502105252251 |
7 | 2610066566615452 |
oct | 306647535106147 |
9 | 53335371808854 |
10 | 13663322016871 |
11 | 439864509283a |
12 | 1648062a94087 |
13 | 7815a4393557 |
14 | 35344602a499 |
15 | 18a633708a81 |
hex | c6d3d748c67 |
13663322016871 has 2 divisors, whose sum is σ = 13663322016872. Its totient is φ = 13663322016870.
The previous prime is 13663322016853. The next prime is 13663322016889. The reversal of 13663322016871 is 17861022336631.
It is a balanced prime because it is at equal distance from previous prime (13663322016853) and next prime (13663322016889).
It is a cyclic number.
It is not a de Polignac number, because 13663322016871 - 217 = 13663321885799 is a prime.
It is a super-2 number, since 2×136633220168712 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13663322016371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6831661008435 + 6831661008436.
It is an arithmetic number, because the mean of its divisors is an integer number (6831661008436).
Almost surely, 213663322016871 is an apocalyptic number.
13663322016871 is a deficient number, since it is larger than the sum of its proper divisors (1).
13663322016871 is an equidigital number, since it uses as much as digits as its factorization.
13663322016871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 49.
The spelling of 13663322016871 in words is "thirteen trillion, six hundred sixty-three billion, three hundred twenty-two million, sixteen thousand, eight hundred seventy-one".
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