Base | Representation |
---|---|
bin | 1100011011010100011000… |
… | …0000000111100001001101 |
3 | 1210101012210101201011210111 |
4 | 3012311012000013201031 |
5 | 3242330234120420433 |
6 | 45020524230440021 |
7 | 2610103260445252 |
oct | 306650600074115 |
9 | 53335711634714 |
10 | 13663465404493 |
11 | 4398709019003 |
12 | 16480a2b03011 |
13 | 7815c7cb87b8 |
14 | 35345b0b3429 |
15 | 18a6410cddcd |
hex | c6d4600784d |
13663465404493 has 2 divisors, whose sum is σ = 13663465404494. Its totient is φ = 13663465404492.
The previous prime is 13663465404487. The next prime is 13663465404517. The reversal of 13663465404493 is 39440456436631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10468673794089 + 3194791610404 = 3235533^2 + 1787398^2 .
It is a cyclic number.
It is not a de Polignac number, because 13663465404493 - 221 = 13663463307341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13663465404443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6831732702246 + 6831732702247.
It is an arithmetic number, because the mean of its divisors is an integer number (6831732702247).
Almost surely, 213663465404493 is an apocalyptic number.
It is an amenable number.
13663465404493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13663465404493 is an equidigital number, since it uses as much as digits as its factorization.
13663465404493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67184640, while the sum is 58.
The spelling of 13663465404493 in words is "thirteen trillion, six hundred sixty-three billion, four hundred sixty-five million, four hundred four thousand, four hundred ninety-three".
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