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136646254853 is a prime number
BaseRepresentation
bin111111101000011000…
…0000110000100000101
3111001201010000222021222
41333100300012010011
54214322420123403
6142435135250125
712605136000443
oct1772060060405
9431633028258
10136646254853
1152a51280839
1222596679945
13cb68b12a04
146884061b93
15384b5a4338
hex1fd0c06105

136646254853 has 2 divisors, whose sum is σ = 136646254854. Its totient is φ = 136646254852.

The previous prime is 136646254841. The next prime is 136646254859. The reversal of 136646254853 is 358452646631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83507706529 + 53138548324 = 288977^2 + 230518^2 .

It is a cyclic number.

It is not a de Polignac number, because 136646254853 - 210 = 136646253829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 136646254795 and 136646254804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136646254859) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68323127426 + 68323127427.

It is an arithmetic number, because the mean of its divisors is an integer number (68323127427).

Almost surely, 2136646254853 is an apocalyptic number.

It is an amenable number.

136646254853 is a deficient number, since it is larger than the sum of its proper divisors (1).

136646254853 is an equidigital number, since it uses as much as digits as its factorization.

136646254853 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12441600, while the sum is 53.

The spelling of 136646254853 in words is "one hundred thirty-six billion, six hundred forty-six million, two hundred fifty-four thousand, eight hundred fifty-three".