Base | Representation |
---|---|
bin | 1100011011011000101111… |
… | …0010111001101001000111 |
3 | 1210101022211000001010001211 |
4 | 3012312023302321221013 |
5 | 3242340133401014103 |
6 | 45021240340032251 |
7 | 2610144266332555 |
oct | 306661362715107 |
9 | 53338730033054 |
10 | 13664636344903 |
11 | 4399159a86955 |
12 | 164836b092687 |
13 | 78175377704b |
14 | 35352c7dabd5 |
15 | 18a6adcc936d |
hex | c6d8bcb9a47 |
13664636344903 has 2 divisors, whose sum is σ = 13664636344904. Its totient is φ = 13664636344902.
The previous prime is 13664636344883. The next prime is 13664636344913. The reversal of 13664636344903 is 30944363646631.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (30944363646631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13664636344903 - 25 = 13664636344871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13664636344913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6832318172451 + 6832318172452.
It is an arithmetic number, because the mean of its divisors is an integer number (6832318172452).
Almost surely, 213664636344903 is an apocalyptic number.
13664636344903 is a deficient number, since it is larger than the sum of its proper divisors (1).
13664636344903 is an equidigital number, since it uses as much as digits as its factorization.
13664636344903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60466176, while the sum is 58.
The spelling of 13664636344903 in words is "thirteen trillion, six hundred sixty-four billion, six hundred thirty-six million, three hundred forty-four thousand, nine hundred three".
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