Base | Representation |
---|---|
bin | 10011111000101001010… |
… | …001110000001100110011 |
3 | 11211122011012000010012001 |
4 | 103320221101300030303 |
5 | 134342033440313414 |
6 | 2523431404314431 |
7 | 200503643241256 |
oct | 23705121601463 |
9 | 4748135003161 |
10 | 1366492119859 |
11 | 4875871a4a69 |
12 | 1a0a03542a17 |
13 | 9bb23876769 |
14 | 4a1d235109d |
15 | 2582b5be074 |
hex | 13e29470333 |
1366492119859 has 2 divisors, whose sum is σ = 1366492119860. Its totient is φ = 1366492119858.
The previous prime is 1366492119847. The next prime is 1366492119871. The reversal of 1366492119859 is 9589112946631.
It is a balanced prime because it is at equal distance from previous prime (1366492119847) and next prime (1366492119871).
It is a cyclic number.
It is not a de Polignac number, because 1366492119859 - 213 = 1366492111667 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1366492119859.
It is not a weakly prime, because it can be changed into another prime (1366492119899) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 683246059929 + 683246059930.
It is an arithmetic number, because the mean of its divisors is an integer number (683246059930).
Almost surely, 21366492119859 is an apocalyptic number.
1366492119859 is a deficient number, since it is larger than the sum of its proper divisors (1).
1366492119859 is an equidigital number, since it uses as much as digits as its factorization.
1366492119859 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25194240, while the sum is 64.
The spelling of 1366492119859 in words is "one trillion, three hundred sixty-six billion, four hundred ninety-two million, one hundred nineteen thousand, eight hundred fifty-nine".
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