Base | Representation |
---|---|
bin | 1100011011101111101110… |
… | …0111100110101101110001 |
3 | 1210101220202001222011020101 |
4 | 3012323323213212231301 |
5 | 3242440303143234111 |
6 | 45024140543112401 |
7 | 2610453231411004 |
oct | 306737347465561 |
9 | 53356661864211 |
10 | 13670807399281 |
11 | 43a083641a39a |
12 | 16495b18a2701 |
13 | 7821c8104006 |
14 | 35395621553b |
15 | 18a92094ebc1 |
hex | c6efb9e6b71 |
13670807399281 has 2 divisors, whose sum is σ = 13670807399282. Its totient is φ = 13670807399280.
The previous prime is 13670807399279. The next prime is 13670807399287. The reversal of 13670807399281 is 18299370807631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13460203504225 + 210603895056 = 3668815^2 + 458916^2 .
It is a cyclic number.
It is not a de Polignac number, because 13670807399281 - 21 = 13670807399279 is a prime.
It is a super-3 number, since 3×136708073992813 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 13670807399279, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13670807399287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6835403699640 + 6835403699641.
It is an arithmetic number, because the mean of its divisors is an integer number (6835403699641).
Almost surely, 213670807399281 is an apocalyptic number.
It is an amenable number.
13670807399281 is a deficient number, since it is larger than the sum of its proper divisors (1).
13670807399281 is an equidigital number, since it uses as much as digits as its factorization.
13670807399281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27433728, while the sum is 64.
The spelling of 13670807399281 in words is "thirteen trillion, six hundred seventy billion, eight hundred seven million, three hundred ninety-nine thousand, two hundred eighty-one".
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