Search a number
-
+
13675088635517 is a prime number
BaseRepresentation
bin1100011011111111101011…
…0011001110011001111101
31210102022210102212111021102
43012333322303032121331
53243023040142314032
645030125440542445
72610664305334211
oct306777263163175
953368712774242
1013675088635517
1143a2633031561
12164a3a7621a25
1378272b0839aa
14353c40a56941
1518aac1729362
hexc6ffacce67d

13675088635517 has 2 divisors, whose sum is σ = 13675088635518. Its totient is φ = 13675088635516.

The previous prime is 13675088635499. The next prime is 13675088635519. The reversal of 13675088635517 is 71553688057631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8251681385476 + 5423407250041 = 2872574^2 + 2328821^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13675088635517 is a prime.

Together with 13675088635519, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13675088635519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6837544317758 + 6837544317759.

It is an arithmetic number, because the mean of its divisors is an integer number (6837544317759).

Almost surely, 213675088635517 is an apocalyptic number.

It is an amenable number.

13675088635517 is a deficient number, since it is larger than the sum of its proper divisors (1).

13675088635517 is an equidigital number, since it uses as much as digits as its factorization.

13675088635517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 127008000, while the sum is 65.

The spelling of 13675088635517 in words is "thirteen trillion, six hundred seventy-five billion, eighty-eight million, six hundred thirty-five thousand, five hundred seventeen".