13680241301 has 2 divisors, whose sum is σ = 13680241302. Its totient is φ = 13680241300.

The previous prime is 13680241283. The next prime is 13680241303. The reversal of 13680241301 is 10314208631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10053070225 + 3627171076 = 100265^2 + 60226^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13680241301 is a prime.

Together with 13680241303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13680241303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6840120650 + 6840120651.

It is an arithmetic number, because the mean of its divisors is an integer number (6840120651).

Almost surely, 2^13680241301 is an apocalyptic number.

It is an amenable number.

13680241301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13680241301 is an equidigital number, since it uses as much as digits as its factorization.

13680241301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 13680241301 its reverse (10314208631), we get a palindrome (23994449932).

The spelling of 13680241301 in words is "thirteen billion, six hundred eighty million, two hundred forty-one thousand, three hundred one".