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13680241409 is a prime number
BaseRepresentation
bin11001011110110011…
…11110101100000001
31022022101210021020202
430233121332230001
5211004120211114
610141251014545
7663003063512
oct145731765401
938271707222
1013680241409
11589015993a
12279959a455
1313a02b3803
1493ac3ca09
1555101ecde
hex32f67eb01

13680241409 has 2 divisors, whose sum is σ = 13680241410. Its totient is φ = 13680241408.

The previous prime is 13680241363. The next prime is 13680241451. The reversal of 13680241409 is 90414208631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11476408384 + 2203833025 = 107128^2 + 46945^2 .

It is an emirp because it is prime and its reverse (90414208631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13680241409 is a prime.

It is not a weakly prime, because it can be changed into another prime (13680241009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6840120704 + 6840120705.

It is an arithmetic number, because the mean of its divisors is an integer number (6840120705).

Almost surely, 213680241409 is an apocalyptic number.

It is an amenable number.

13680241409 is a deficient number, since it is larger than the sum of its proper divisors (1).

13680241409 is an equidigital number, since it uses as much as digits as its factorization.

13680241409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 13680241409 in words is "thirteen billion, six hundred eighty million, two hundred forty-one thousand, four hundred nine".