Base | Representation |
---|---|
bin | 11001011110110011… |
… | …11110101100101011 |
3 | 1022022101210021022022 |
4 | 30233121332230223 |
5 | 211004120211301 |
6 | 10141251015055 |
7 | 663003063602 |
oct | 145731765453 |
9 | 38271707268 |
10 | 13680241451 |
11 | 5890159978 |
12 | 279959a48b |
13 | 13a02b3836 |
14 | 93ac3ca39 |
15 | 55101ed1b |
hex | 32f67eb2b |
13680241451 has 2 divisors, whose sum is σ = 13680241452. Its totient is φ = 13680241450.
The previous prime is 13680241409. The next prime is 13680241453. The reversal of 13680241451 is 15414208631.
13680241451 is nontrivially palindromic in base 14.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13680241451 - 226 = 13613132587 is a prime.
Together with 13680241453, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13680241453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6840120725 + 6840120726.
It is an arithmetic number, because the mean of its divisors is an integer number (6840120726).
Almost surely, 213680241451 is an apocalyptic number.
13680241451 is a deficient number, since it is larger than the sum of its proper divisors (1).
13680241451 is an equidigital number, since it uses as much as digits as its factorization.
13680241451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 35.
The spelling of 13680241451 in words is "thirteen billion, six hundred eighty million, two hundred forty-one thousand, four hundred fifty-one".
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