Base | Representation |
---|---|
bin | 10011111010000110011… |
… | …001011001111001011111 |
3 | 11211210012001201111220112 |
4 | 103322012121121321133 |
5 | 134403233412004001 |
6 | 2524250413440235 |
7 | 200560443406454 |
oct | 23720631317137 |
9 | 4753161644815 |
10 | 1368054406751 |
11 | 48820905825a |
12 | 1a117a7a007b |
13 | 9c012436886 |
14 | 4a2dda2982b |
15 | 258bd81dcbb |
hex | 13e86659e5f |
1368054406751 has 2 divisors, whose sum is σ = 1368054406752. Its totient is φ = 1368054406750.
The previous prime is 1368054406699. The next prime is 1368054406753. The reversal of 1368054406751 is 1576044508631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1368054406751 - 26 = 1368054406687 is a prime.
Together with 1368054406753, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1368054406751.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1368054406753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684027203375 + 684027203376.
It is an arithmetic number, because the mean of its divisors is an integer number (684027203376).
Almost surely, 21368054406751 is an apocalyptic number.
1368054406751 is a deficient number, since it is larger than the sum of its proper divisors (1).
1368054406751 is an equidigital number, since it uses as much as digits as its factorization.
1368054406751 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 50.
The spelling of 1368054406751 in words is "one trillion, three hundred sixty-eight billion, fifty-four million, four hundred six thousand, seven hundred fifty-one".
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