Base | Representation |
---|---|
bin | 111111101110100110… |
… | …1011101110111001111 |
3 | 111002020200100121101221 |
4 | 1333131031131313033 |
5 | 4220234422443403 |
6 | 142512003344211 |
7 | 12613254460432 |
oct | 1773515356717 |
9 | 432220317357 |
10 | 136855281103 |
11 | 53049269302 |
12 | 22634682067 |
13 | cba020a598 |
14 | 68a3b13819 |
15 | 385eae2dbd |
hex | 1fdd35ddcf |
136855281103 has 2 divisors, whose sum is σ = 136855281104. Its totient is φ = 136855281102.
The previous prime is 136855281071. The next prime is 136855281131. The reversal of 136855281103 is 301182558631.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136855281103 - 25 = 136855281071 is a prime.
It is a super-2 number, since 2×1368552811032 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 136855281103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136855281403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68427640551 + 68427640552.
It is an arithmetic number, because the mean of its divisors is an integer number (68427640552).
Almost surely, 2136855281103 is an apocalyptic number.
136855281103 is a deficient number, since it is larger than the sum of its proper divisors (1).
136855281103 is an equidigital number, since it uses as much as digits as its factorization.
136855281103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 43.
The spelling of 136855281103 in words is "one hundred thirty-six billion, eight hundred fifty-five million, two hundred eighty-one thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •