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136906242131 is a prime number
BaseRepresentation
bin111111110000000111…
…1110111100001010011
3111002101020020200210102
41333200033313201103
54220340444222011
6142521023523015
712614443600031
oct1774017674123
9432336220712
10136906242131
115307500605a
122264975946b
13cbaa941239
1468aa7bb551
15386430c73b
hex1fe03f7853

136906242131 has 2 divisors, whose sum is σ = 136906242132. Its totient is φ = 136906242130.

The previous prime is 136906242113. The next prime is 136906242133. The reversal of 136906242131 is 131242609631.

Together with previous prime (136906242113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136906242131 is a prime.

It is a super-2 number, since 2×1369062421312 (a number of 23 digits) contains 22 as substring.

Together with 136906242133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (136906242133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68453121065 + 68453121066.

It is an arithmetic number, because the mean of its divisors is an integer number (68453121066).

Almost surely, 2136906242131 is an apocalyptic number.

136906242131 is a deficient number, since it is larger than the sum of its proper divisors (1).

136906242131 is an equidigital number, since it uses as much as digits as its factorization.

136906242131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 136906242131 in words is "one hundred thirty-six billion, nine hundred six million, two hundred forty-two thousand, one hundred thirty-one".