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13700064521200 = 24523113117348751
BaseRepresentation
bin1100011101011100101101…
…1110101010101111110000
31210111201021001101221110111
43013113023132222233300
53243430213004134300
645045420040511104
72612540241012361
oct307271336525760
953451231357414
1013700064521200
11440218a2980a2
1216531b7a7b494
13784bab5c6185
1435512db23b68
1518b5842369ba
hexc75cb7aabf0

13700064521200 has 240 divisors, whose sum is σ = 34434119503872. Its totient is φ = 5232240000000.

The previous prime is 13700064521179. The next prime is 13700064521233. The reversal of 13700064521200 is 212546000731.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 280996825 + ... + 281045575.

Almost surely, 213700064521200 is an apocalyptic number.

13700064521200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13700064521200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17217059751936).

13700064521200 is an abundant number, since it is smaller than the sum of its proper divisors (20734054982672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13700064521200 is a wasteful number, since it uses less digits than its factorization.

13700064521200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49104 (or 49093 counting only the distinct ones).

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 13700064521200 in words is "thirteen trillion, seven hundred billion, sixty-four million, five hundred twenty-one thousand, two hundred".